[MD] constant

[Horse]

  Hi Marsha
It probably depends on what you mean by a vacuum but I was having an 
interesting conversation with a friend of mine yesterday about C.
Apparently, from what I gather he was talking about, C is no longer a 
constant but is dependent upon the curvature of space - i.e. if there is 
a gravitational difference in one area of the universe compared to 
another area (E.g. a singularity) then there will be a difference in the 
value of C! The greater the effect of gravity the slower C becomes and 
thus time is affected. So in areas of high gravitation time is slower 
than in areas of lower gravitation. Weird? Maybe. The Standard Model has 
been in a bit of a mess recently and I don't suppose that this helps too 
much.
This also, apparently, has implications for the age of the universe as 
in the early stages of the universe overall gravity would have been much 
greater so time would have been slower which means, I think, that the 
universe could be older than has been assumed!!!!! It could also mean 
that as the universe expands and average gravity value decreases time 
speeds up. Which may also be a factor in the apparent increase in the 
speed of expansion of the universe. Maybe! All pretty mind-blowing but 
very interesting.
I'm sure this idea has been around for a while but I can't find specific 
references to it at the moment but I think there was an article recently 
in either New Scientist or Scientific American relating to some new 
ideas on the subject and how it relates to a reduction in the amount of 
dark energy/matter required to make various sums add up properly. Anyone 
else heard anything about this? Or am I becoming delusional as I get 
older? Which is entirely possible!

Horse



On 02/09/2010 07:58, MarshaV wrote:
> Greetings,
>
> It is my understanding that the usefulness of c is dependent
> on it existing within a vacuum, a vacuum which does not
> exist, is this true?   Anybody know?
>
>
>
> Marsha
>
>
>
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